Math, asked by ravipaswan1603, 11 months ago

How do you solve x−2(3x−1)=7(3−2x)?

Answers

Answered by archi193063

0

X-2(3x-1)=7(3-2x)

X-6x+2=21-14x

5x+2=21-14x

5x+14x=21-2

19x=19

X=19/19

X=0

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