Question

How do you solve ⎡⎢ ⎢ ⎢ ⎢⎣−x+2y−4z−5u=27−2x−3y+3z−3u=95x−4y+2z−3u=5−2x+0y+4z−5u=29⎤⎥ ⎥ ⎥ ⎥⎦?

Answer 1

fist transpose all the x values

then u values then y values then z values

-x+2x-95x+2x=-3y-2y+4y+0y=4z-3z+2z-4z=5u+3u+3u+5u=-27-5+29

now calculate

-92x=5y=z=16u=-3

x=-3/-92=3/92

y=-3/5

z=-3

u=-3/16