How do you solve x−√3x+7=7?
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Solution:
x-√3x+7 = 7
=> x-7 = √3x+7
On Squaring both sides of the equation, we get
=> (x-7)² = (√3x+7)²
=> x²-14x+49 = 3x+7
=> x²-14x+49-3x-7 = 0
=> x²-17x+42 = 0
Splitting the middle term,we get
=> x²-3x-14x+42=0
=> x(x-3)-14(x-3)=0
=> (x-3)(x-14)=0
=> x-3 = 0 or x -14 = 0
=> x = 3 or x = 14
Therefore,
x = 3 or x = 14
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