How do you solve x2−2x−15=0 using the quadratic formula?
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=>x² - 2x -15 = 0
=>x² - 5x +3x -15=0
=> x(x-5) + 3(x-5)=0
=> (x-5)(x+3)=0
Therefore,
(x-5)=0 & (x+3)=0
x=5 & x =-3
=>x² - 5x +3x -15=0
=> x(x-5) + 3(x-5)=0
=> (x-5)(x+3)=0
Therefore,
(x-5)=0 & (x+3)=0
x=5 & x =-3
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