How do you solve y-2x=6 and x+4y=15?
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y - 2x = 6 -------------(1)
x + 4y = 15 -------------(2)
Multiple the eqⁿ (2) by 2
(x + 4y) 2 = 15 × 2
2x + 8y = 30 -------------(3)
Add eqⁿ (1) and (3), we get
y - 2x + 2x + 8y = 6 + 30
9y = 36
y = 36/9
y = 4
Substitute y =4 in eqⁿ (1), we get
4 - 2x = 6
2x = 4 - 6
2x = - 2
x = - 2/2
x = - 1
Therefore, x = - 1 and y = 4.
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Answered by
0
y - 2x = 6 -------------(1)
x + 4y = 15 -------------(2)
Multiple the eqⁿ (2) by 2
(x + 4y) 2 = 15 × 2
2x + 8y = 30 -------------(3)
Add eqⁿ (1) and (3), we get
y - 2x + 2x + 8y = 6 + 30
9y = 36
y = 36/9
y = 4
Substitute y =4 in eqⁿ (1), we get
4 - 2x = 6
2x = 4 - 6
2x = - 2
x = - 2/2
x = - 1
Therefore, x = - 1 and y = 4.
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