Question

How do you use laws of exponents to simplify (3x3y)2(−4x2y4)3?

Answer 1

Step by step explanation :

$(3x \times 3y) \times 2 \times ( - 4x \times 2y \times 4) \times 3$

Calculate the product by multiplying the numbers.

$= > (9xy) \times 2 \times ( - 4x \times 2y \times 4) \times 3$

Calculate the product

$= > (9xy) \times 2 \times ( - 32xy) \times 3$

Multiplying an odd number of negative factors equals a negative.

$= > - 9xy \times 2 \times 32xy \times 3$

Use rules of multiplication to calculate the expression.

$= > - 1728xyxy$

If a term doesn't have an exponent it is considered that the exponent is 1.

$= > - 1728x {}^{1} y {}^{1} x {}^{1} y {}^{1}$

Multiply the terms with the same base by adding their exponents.

$= > - 1728x {}^{1 + 1} y {}^{1 + 1}$

Add the numbers

$= > - 1728x {}^{2} y {}^{2}$