How do you work out this question: A plane travelling at 100 m/s accelerates at 5 m/s² for a distance of 125 m. What is the final velocity of the plane?
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Answer:
Given: A plane travelling at 100 m/s accelerates at 5 m/s² for a distance of 125 m.
To find: Final velocity of the plane
Solution: Let the initial velocity of the plane be u, final velocity be v, acceleration be a and distance covered be s.
u = 100 m/s
a= 5 m/s²
s=125 m
For finding the final velocity of the plane, the kinematic formula to be used is:
{v}^{2} = {u}^{2} + 2asv
2
=u
2
+2as
= > {v}^{2} = {(100)}^{2} + 2 \times 5 \times 125=>v
2
=(100)
2
+2×5×125
= > {v}^{2} = 10000 + 1250=>v
2
=10000+1250
= > {v}^{2} = 11250=>v
2
=11250
= > v = \sqrt{11250}=>v=
11250
=> v = 106.07 m/s
Therefore, the final velocity of the plane will be 106.07 m/s.
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