how do you work out though the first 2 and the last 2 are small
5xy-x2t+2xy+3x2t
and it wont let me put the symbol ^
Answers
Answered by
4
Step-by-step explanation:
Log in to add comment ... 5xy- 2xy+3x^2t-x^2t. 3xy+2x^ ... For this first take collectively the coefficients of (xy) and (x²t). So,.
Answered by
1
Its 5xy(x+y)2
Explanation:
5xy(x2+2xy+y2)
=5xy(x+y)2or5xy(x+y)(x+y)
Hope that helped.
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