Question

How do you work out Y²-13y+30=-12

Answer 1

Step-by-step explanation:

y² - 13y + 30 = 12

=> y² - 13y + 30 - 12 = 0

=> y² - 13y + 18 = 0

=> y = [- b ±√b² - 4ac] /2a

=> y = [ - (-13) ± √{(-13)² - 4 × 1 × 18 }] / 2 × 1

=> y = [13 ± √(169 - 78)] / 2

=> y = (13 ± √91) / 2

=> y = 13 + 9.54) ) / 2 => 11.27

and

=> y = (13 - 9.64) / 2 => 3.36/2 => 1.68