Question

How do you write 10−2⋅10−8 using only positive exponents?

Answer 1

Solution:

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We know the Exponential Law:

a^-n = 1/aⁿ

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Here,

$10^{-2}\cdot 10^{-8}$

=$\frac{1}{10^{2}}\cdot\frac{1}{10^{8}}$

= $\frac{1}{10^{(2+8)}}$

= $\frac{1}{10^{10}}$

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Answer 2

Hey !

Refer the attachment below !

Thanks!