How do you write a quadratic equation with vertex (-1, 4) and point (-3, - 4)?
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Step-by-step explanation:
y = k(x - a)^2 + b is the equation of a parabola with vertex at (a , b).
y = k(x + 1)^2 + 4
Now since (- 3 , - 4) belongs to the parabola, then - 4 = 4k + 4 and therefore k = - 2. Finally
y = - 2(x + 1)^2 + 4.
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