Question

How do you write an equation of the line containing the given point and perpendicular to the given line: (6, -9); 6x+5y=7?

Answer 1

Answer:

Step-by-step explanation:

For perpendicular lines, the product of the slope is equal to -1.

m1*m2=-1.

Straight lines take the form y=mx+b where m is the slope and b is the y intercept.

For equation 6x+5y=7.

rewriting, 5y=-6x+7

y=-6/5*x+7/5

m1=-6/5.

Therefore m2 is obtained by;

-6/5*m2=-1

m2=5/6

To obtain the equation; (6, -9)(x,y), m=5/6

y--9/x-6=5/6

y+9/x-6=5/6

cross multiplying we get; 6y+54=5x-30

6y=5x-84

y=5/6*x-84/6=5/6*x-14

y=5/6*x-14