Question

How do you write an inequality and solve given "two thirds of a number added to six is at least twenty two"?

Answer 1

Let the no. be x

So , it's two-third = 2/3 of x => 2x/3

According to the question we have :-

2x/3 + 6 = 22

2x/3 = 22 - 6

2x/3 = 16

x = 16 x 3 / 2

So , x = 24

Hence the no. is 24

Hope it helped you...

Answer 2

Answer:Let the no. be x

So , it's two-third = 2/3 of x => 2x/3

According to the question we have :-

2x/3 + 6 = 22

2x/3 = 22 - 6

2x/3 = 16

x = 16 x 3 / 2

So , x = 24

Step-by-step explanation: