How do you write sin3x in terms of sinx?
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Sin3x= Sin(2x+x) = Sin2xCosx+Cos2xSinx = 2SinxCosxCosx + (Cos^2x - Sin^2x) Sinx = 2SinxCos^2x + Cos^2xSinx - Sin^3x
= 3Sinx Cos^2x - Sin^3x
= 3Sinx(1 - Sin^2x) - Sin^3x
= 3Sinx - 3Sin^3x - Sin^3x
= 3Sinx - 4Sin^3x
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Answer:
sin(3x) = sin(x + 2x)
Step-by-step explanation:
this is the right ansqer
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