Math, asked by morngrashi8063, 1 year ago

How do you write the equation in standard form through (-2, 2); perpendicular to y = 4?

Answers

Answered by mkrishnan

0

Answer:

4r−3⋅2r2?

Step-by-step explanation:

perpendicular to y = 4 is parallel to y axis

x = h is the equation

in given point [-2,2] x = -2

4r−3⋅2r2?

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