Question

How do you write the equation of the parabola that has the same shape as y=x2 but that has a vertex of (-3, 2)?

Answer 1

Answer:

∴ y = x² + 6x + 11

Step-by-step explanation:

Any equation of parabola can be represented as y = a(x - h)² + k, where (h,k) is the vertex of the parabola. As it has to be of the same shape as y = x², a will be equal to 1.

∴ y = (x + 3)² + 2

     = x² + 6x + 9 + 2

∴ y = x² + 6x + 11

Hope this helps! :)