Question

How do you write the equation of the quadratic that has the vertex of (2,-3) and a point on (0,1)?

Answer 1

Answer:

Step-by-step explanation:

y = k(x - a)^2 + b  is the equation of a parabola with vertex at (a , b).

y = k(x - 2)^2 - 3

Now since (0 , 1) belongs to the parabola, then  1 = 4k - 3  and therefore  k = 1. Finally

y = (x - 2)^2 - 3.