How do you write the equation y+4=−13(x−12) in standard form?
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Solution:
y+4=-13(x-12)
=> 13(x-12)+y+4=0
=> 13x-156+y+4=0
=> 13x+y-152=0
=> 13x+1y+(-152)=0 Compare
this with ax+by+c=0,we get
a=13,b=1,c= -152
Therefore,
Standard form:
13x+1y-152=0
••••
y+4=-13(x-12)
=> 13(x-12)+y+4=0
=> 13x-156+y+4=0
=> 13x+y-152=0
=> 13x+1y+(-152)=0 Compare
this with ax+by+c=0,we get
a=13,b=1,c= -152
Therefore,
Standard form:
13x+1y-152=0
••••
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