Math, asked by alishanaaz6259, 1 year ago

How do you write the point slope form of the equation given (-3,-3) parallel to y=73x+3?

Answers

Answered by chetanarupeshkumhar
0

y=73x+3

73x-y+3=0

slope(m) =-b/a

=1/73

(-3,-3)

x1=-3

y1=-3

by using slope point form

(y-y1) =m(x-x1)

y+3=1/73(x+3)

this a answer

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