Question

How do you write the standard form of a line given (1/2 , -2/3 ); perpendicular to the line 4x − 8y = 1?

Answer 1

Answer:

Step-by-step explanation:

The standard form of a straight line is given by y=mx+b.

where m is the slope and b is the y intercept.

For perpendicular lines, the product of their slopes is equal to -1.

this is, m1*m2=-1

For line 4x-8y=1,

Rewriting in std form, y =1/2*x-1/8

m=1/2

hence, 1/2*m2=-1

m2=-2

To get the equation, (1/2, -2/3)(x,y), m=-2

y--2/3/x-1/2=-2

y+2/3=-2x+1

y=-2x+1/3