How does angular momentum evolve with time quantum mechanics?
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The time dependence does not disappear but it appears as another form such as Schrödinger representation, where states become time-dependent and operators are time-Independent....
But there are unitary transformations to pass from one representation to another....
We can use the evolution operator, for example, to pass from as Schrödinger representation to Heisenberg representation....
But there are unitary transformations to pass from one representation to another....
We can use the evolution operator, for example, to pass from as Schrödinger representation to Heisenberg representation....
ShraddhaRajput:
hello
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Hello mate here is your answer.
The operators of all observables are time-independent in the so-called Schrödinger picture of quantum mechanics. This is not the case in the two other pictures, known as the Heisenberg picture and the Interaction picture. Operators in the latter two pictures are dynamical, their dynamics being governed by the appropriate equations of motion. For details, see the initial sections of Chapter 3 of the book Quantum Theory of Many-Particle Systems.
Hope it helps you.
The operators of all observables are time-independent in the so-called Schrödinger picture of quantum mechanics. This is not the case in the two other pictures, known as the Heisenberg picture and the Interaction picture. Operators in the latter two pictures are dynamical, their dynamics being governed by the appropriate equations of motion. For details, see the initial sections of Chapter 3 of the book Quantum Theory of Many-Particle Systems.
Hope it helps you.
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