How does coordination number influence the magnitude of ionic ready?
Answers
From the formula? Yeah. Let's take three examples.
(1) [Fe(NH3)6]2+
Simply from the formula, we see that there are six NH3 ligands bound to iron ion. Each coordinated NH3contributes 0 charge, so the oxidation state of iron is +2. Therefore, the metal ion is called iron(II).
Since six ligands are bound, the coordination number of Fe2+ is 6.
The full name of this compound is hexammineiron(II).
(2) [Ag(NH3)2]+
Simply from the formula, we see that there are two NH3 ligands bound to silver ion. Each coordinated NH3contributes 0 charge, so the oxidation state of silver is +1. Therefore, the metal ion is called silver(I).
Since two ligands are bound, the coordination number of Ag+ is 2.
The full name of this compound is diamminesilver(I).
(3) CoCl4
Simply from the formula, we see that there are four Cl ligands bound to cobalt ion. Each coordinated Clcontributes −1 charge, so the oxidation state of cobalt is +4. Therefore, the metal ion is called cobalt(IV).
Since four ligands are bound, the coordination number of Co2+ is 4.
The full name of this compound is tetrachlorocobalt(II).
Explanation:
Covalently Bonded Molecules
In a covalently bonded molecule, chemists determine the coordination number of the central atom by counting the number of bonded atoms. ... For example, the coordination number of the carbon trioxide molecule (CO3)2- is 3, and the charge of the ion is -2.