How does it explain that Bi(5+) is stronger oxidant than P(5+)?
Answers
Answered by
0
Answer:
Both Sb and Bi are same group elements and as we go down the group then due to inert pair effect there will be increase in +3 oxidation state. Hence, Bi being the last element easily gains two electrons and reduces to +3 oxidation state from +5. Therefore, Bi(V) acts as a stronger oxidant than Ab(V).
Similar questions