How does K.E of an object change if its momentum is doubled
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Kinetic energy = 0.5mv^2
Momentum = mv
From above two equations relation between Kinetic energy (K) and momentum (p) is
K = p^2 / (2m)
For an object of mass m
K ∝ p^2
So, if p is doubled K will be quadrupled.
K₂ = 4 K₁
Momentum = mv
From above two equations relation between Kinetic energy (K) and momentum (p) is
K = p^2 / (2m)
For an object of mass m
K ∝ p^2
So, if p is doubled K will be quadrupled.
K₂ = 4 K₁
CherubB:
Thank you very much
You’re welcome
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