Question

How does kezia begin to see her father as a human being who need her sympathy?​

Answer 1

Explanation:

Answer: When Kezia's mother falls sick she is feeling lonely. ... When her father falls asleep before her, she realizes that her father is also a human being and he too needs sympathy.

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Answer 2

$\large\underline{\sf{Given - }}$

$\sf \: An \: equation : {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\: having \: one \: root \: 1 + i$

$\begin{gathered}\begin{gathered}\sf \: To\: Find - \begin{cases} &\sf{remaining \: roots \: of \: equation}  \end{cases}\end{gathered}\end{gathered}$

$\sf\large\underline{Solution-}$

Given equation is :-

$\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0$

As we know that complex roots occur in conjugate pairs.Therefore, 1 - i will be the other root of the given equation.

$\sf \red{\: \:\bigg( x - (1 + i)\bigg) \bigg(x - (1 - i) \bigg)}$

$\sf \: :\implies \: (x - 1 - i)(x - 1 + i)$

$\sf \: :\implies {(x - 1)}^{2} - {i}^{2}$

$\sf \: :\implies {x}^{2} + 1 - 2x - ( - 1) \: \: \: \: \: ( \sf \red{\because \: {i}^{2} = - 1)}$

$\sf \: :\implies {x}^{2} - 2x + 2$

$\sf \:\red{ {x}^{2} - 2x + 2 }\: is \: a \: factor \: of \: given \: equation.$

On Dividing :-

$\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 \: by \: {x}^{2} - 2x + 2 \: we \: will \: get \:$

$\sf \: \pink{ {x}^{2} + 4x + 1}$

$\sf \green {[For \: details \: see \: the \:attachment ]}$

$\sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\:$

$\sf :\implies\: ({x}^{2} - 2x + 2)( {x}^{2} + 4x + 1) = 0$

$\rm :\implies \: {x}^{2} + 4x + 1 = 0$

On comparing it with ax² + bx + c = 0, we have

• a = 1

• b = 4

• c = 1

Roots of the equation is given by:-

$\sf :\implies\:\sf \: x \: = \: \dfrac{ - b \: \pm \: \sqrt{ {b}^{2} - 4ac} }{2a}$

$\sf :\implies \:x \: = \: \dfrac{ - 4 \: \pm \: \sqrt{ {4}^{2} - 4 \times 1 \times 1} }{2 \times 1}$

$\sf :\implies \:x = \dfrac{ - 4 \: \pm \: \sqrt{12} }{2}$

$\sf :\implies \:x = \dfrac{ - 4 \: \pm \: 2\sqrt{3} }{2}$

$\sf :\implies \purple{ \:x \: = \: - 2 \: \pm \: \sqrt{3} }$

$\therefore \sf \: The \: roots \: of \: \sf \: {x}^{4} + {2x}^{3} - {5x}^{2} + 6x + 2 = 0\: \: are$

$\sf\purple{\: 1 + i},\red{ \: 1 - i},\green{ \: - 2 + \sqrt{3} } \: and\pink {\: - 2 - \sqrt{3}}$