How does NaBH4 react with iodine?
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First, iodine is reacting with one sodium borohydride, so you get borane, sodium iodide, and hydrogen iodide. Then hydrogen iodide is reacting with another sodium borohydride, so you get another borane and another sodium iodide, plus some hydrogen. All that borane is actually the stuff that reduces the acid to alcohol.
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Q) How does NaBH4 react with iodine?
Answer:- First, iodine is reacting with one sodium borohydride, so you get boronae, sodium iodide, and hydrogen iodide. Thus hydrogen iodide is reacting with another sodium borohydride, so you get another boronae and another sodium iodide plus same hydrogen. All that botane is actually the stuff that reduces the acid to alcohol.
Answer:- First, iodine is reacting with one sodium borohydride, so you get boronae, sodium iodide, and hydrogen iodide. Thus hydrogen iodide is reacting with another sodium borohydride, so you get another boronae and another sodium iodide plus same hydrogen. All that botane is actually the stuff that reduces the acid to alcohol.
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