How does surface density of charge depend on (1) curvature of the body (2) radius of curvature of the body?for 1 mark question
Answers
Answered by
0
Answer:
Answer: We mathematically prove that surface charge density of a conductor at a particular region on its surface is inversely proportional to the radius of curvature at that region using 2 spheres. This means that the smaller sphere has the greater charge density (for a given potential).
please mark as brainlest answer
Similar questions