Question

How does the acceleration due to gravity (g) change for the same values of height (h) and depth (d).

Answer 1

we know, acceleration due to gravity at a height h from the surface of the earth is given by, $g=\frac{g_0}{\left(1+\frac{h}{R}\right)^2}$

hence, for h > 0 , acceleration due to gravity decreases and will be less than acceleration due to gravity on earth's surface{e.g., $g_0$ at the earth's surface. }

Acceleration due to gravity at depth (d) from the surface of the earth is given by,
$g=g_0\left(1-\frac{d}{R}\right)$

here for d > 0 , acceleration due to gravity decreases and becomes less than acceleration due to gravity on the surface of the earth.

so, we conclude that, acceleration due to gravity on earth's surface becomes maximum. it decreases , either we go up or down from the earth's surface.

Answer 2

we know acceleration is due gravity