How does the coefficient of friction chnange if mass of body is double?
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solution:
let us prove that,
coefficient of friction(\mu)=f/n ------(1)
where f is friction force, and the normal N =mass\times g\\
then by substituting N in the equation 1
we get,
\mu = f/m x g --------------------(2)
now we can observe from equation 2 that as the mass increases the coefficient of friction \mu will decrease. so if the mass doubled the coefficient of friction will be decrease.
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Answer:Formal charges help in the selection of the lowest energy structure from the number of possible
Lewis structure.
Lowest energy structure is the one with a factor based on a pure covalent bond between the two
atoms.
Explanation:
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