How does the coloumb force between two point charges depend upon the dielectric constant of the medium?
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The coulomb force between two charges decreases when a dielectric medium is placed in between the charges.
F=14πε0εr×q1q2r2Force is inversly proportional to εrεr is called the dielectric constant of medium
F=14πε0εr×q1q2r2Force is inversly proportional to εrεr is called the dielectric constant of medium
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please make my answer as brainiest answer
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the formula is q=1/4⚻Eo x q1q2/r^2
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