how does the current travel (drift velocity)concept
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Hii dear.....
Here is ur answer..
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# The drift velocity of an electron is speed of electron travel under the influence of applied voltage, which creates an Electrical Field. Under such a condition, the electrons travel in an orderly directions like soldiers [ ELECTRONS} under the command of captain [ VOLTAGE and hence FIELD]......
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#^^DREAMER $ ^^
Here is ur answer..
________
# The drift velocity of an electron is speed of electron travel under the influence of applied voltage, which creates an Electrical Field. Under such a condition, the electrons travel in an orderly directions like soldiers [ ELECTRONS} under the command of captain [ VOLTAGE and hence FIELD]......
________________
#^^DREAMER $ ^^
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So there are two things that seem to be wound together in your question. You are concerned with how big the current is when the electrons move so slowly. You also may be wondering how the light goes on so quickly when it would take hours for an electron to travel from the switch to the light.
The first possible concern is the current, which does indeed depend on the speed of the electrons… but also on how many electronsare flowing. In a given length of time, say a second, the electrons in a wire only move a few millimetres. But those few millimetres of wire contain a lot of electrons.
Let’s suppose a copper wire is round and has a diameter of 2 mm. Then the cross sectional area is about [math]3 \times 10^{-6} m^2[/math] in cross section. If the drift speed of the electrons is 1 mm/s then only [math]3 \times 10^{-9} m^3[/math] worth of electrons move through the wire every second.
The first possible concern is the current, which does indeed depend on the speed of the electrons… but also on how many electronsare flowing. In a given length of time, say a second, the electrons in a wire only move a few millimetres. But those few millimetres of wire contain a lot of electrons.
Let’s suppose a copper wire is round and has a diameter of 2 mm. Then the cross sectional area is about [math]3 \times 10^{-6} m^2[/math] in cross section. If the drift speed of the electrons is 1 mm/s then only [math]3 \times 10^{-9} m^3[/math] worth of electrons move through the wire every second.
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