How does the electric flux electric field enclosing a given area enclosed by the charge is doubled
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Electric flux will remain Constant
Electric flux φ = E.ΔS
where ΔS is the area element.
Now when ΔS = 2ΔS
then φ = E.2ΔS
or, φ = 2E.ΔS
thus doubling the area will double the flux.
But in the case given in question ,the guassian surface area enclosing the charge is doubled then in such a case the flux will remain unchanged.
and electric field E is halved.
hope it helps
please make it brainlist
Electric flux φ = E.ΔS
where ΔS is the area element.
Now when ΔS = 2ΔS
then φ = E.2ΔS
or, φ = 2E.ΔS
thus doubling the area will double the flux.
But in the case given in question ,the guassian surface area enclosing the charge is doubled then in such a case the flux will remain unchanged.
and electric field E is halved.
hope it helps
please make it brainlist
Arshim1:
thanks bro
Answered by
1
electric flux is directly proportional to the magneticfield
so we can double the flux by doubling the field or current or potential difference.
Good luck
mark it as brainliest
so we can double the flux by doubling the field or current or potential difference.
Good luck
mark it as brainliest
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