How does the electric potential due to a short electric dipole vary with distance?
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It changes inversely as a function of r*3, where r is the needed distance from the dipole's center to the measurement location for the electric field.
Explanation:
In contrast to a single charge's 1/r^2 nature, an electric dipole's two opposed charges cause the electric field to decay more quickly. In actuality, the field for the electric dipole shrinks as 1/r^3 with distance. In terms of angle around the dipole, it is likewise not symmetrical.
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