Question

How does the fluid pressure on a balloon changes when-
a. balloon rises up from a height of 200m to a height of
500m?
b. balloon moves horizontally at a height of 200 m?



give me the answer but remember that it is of 1 marks​

Answer 1

Answer:

The pressure on a balloon is 2.94\times10^{6}\ Pa2.94×10

6

Pa

Explanation:

Given that,

Initial height = 200 m

Final height = 500 m

We need to calculate the pressure on a balloon

Using formula of pressure

P=\rho g (h_{2}-h_{1})P=ρg(h

2

−h

1

)

Where, \rhoρ = density of water

g = acceleration due to gravity

h = height

Put the value into the formula

P=1000\times9.8(500-200)P=1000×9.8(500−200)

P=2.94\times10^{6}\ PaP=2.94×10

6

Pa

Hence, The pressure on a balloon is 2.94\times10^{6}\ Pa2.94×10

6

Pa