How does the force between two objects change when the distance them is reduced to 1/3?
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F=GMm/d^2
Now, d=d/3
So,
F=GMm/((d/3)^2)
F=GMm/((d^2)/9)
F=GMm*9/d^2
F=9(GMm/d^2)
F=9F
Hence, if distance is reduced to 1/3, force will be 9 times.
Now, d=d/3
So,
F=GMm/((d/3)^2)
F=GMm/((d^2)/9)
F=GMm*9/d^2
F=9(GMm/d^2)
F=9F
Hence, if distance is reduced to 1/3, force will be 9 times.
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