Question

How does the force of gravitation between two objects change when the distance between them is reduced to half ?​

Answer 1

Answer:  As force of gravitation is inversely proportional to the square of the distance of separation-

i.e.  g ∝ $\frac{1}{r^2\\}$

the gravitation force of attraction between them will be Four times when distance of separation is reduced to half.

Mathematically-

g = $\frac{1}{r^2}$

g = $\frac{1} {(\frac{1}{2} )^2}$

g= $\frac{1}{\frac{1}{4\\} }$

g= 4    ans.

Answer 2

Answer:

Answer: As force of gravitation is inversely proportional to the square of the distance of separation-

i.e. g ∝ \begin{gathered}\frac{1}{r^2\\}\end{gathered}

the gravitation force of attraction between them will be Four times when distance of separation is reduced to half.

Mathematically-

g = \frac{1}{r^2}

r

2

1

g = \frac{1} {(\frac{1}{2} )^2}

(

2

1

)

2

1

g= \begin{gathered}\frac{1}{\frac{1}{4\\} }\end{gathered}

g= 4 ans.