How does the force of gravitation between two objects change when their distance is reduces to half?
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Answered by
3
F=GMm/(d^2)
Now, d=d/2
So,
F=GMm/((d/2)^2)
F=GMm/((d^2)/4)
F=GMm*4/(d^2)
F=4*(GMm/(d^2))
F=4F
Hence, if distance is reduced to half, force will become 4 times.
Now, d=d/2
So,
F=GMm/((d/2)^2)
F=GMm/((d^2)/4)
F=GMm*4/(d^2)
F=4*(GMm/(d^2))
F=4F
Hence, if distance is reduced to half, force will become 4 times.
Answered by
1
☺ Hello mate__ ❤
◾◾here is your answer...
According to the universal law of gravitation, gravitational force (F),
F∝ 1/r^2
If distance r becomes r/2, then the gravitational force will be proportional to
F ∝ 1/ (r/2)^2 ∝ 4/r^2
Hence, if the distance is reduced to half, then the gravitational force becomes four times larger than the previous value.
I hope, this will help you.
Thank you______❤
✿┅═══❁✿ Be Brainly✿❁═══┅✿
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