how does the force of gravitation between two objects change when the distance between them is reduced to half
Anonymous:
fb
Answers
Answered by
2
F=G(m1m2)/r^2
therfore F is inversely proportional to r squared
let F1=F
r1=r
r2=r/2
F2=?
F1/F2=(r2)^2/(r1)^2
F/F2=(r/2)^2/(r)^2
F/F2=1/4
F2=4F
thus if distance between them is reduced to 1/2 then gravitational force becomes 4 times
Answered by
0
Answer:
According to the universal law of gravitation, gravitational force (F) acting between
two objects is inversely proportional to the square of the distance (r)
between them, i.e.,
If distance r becomes r/2, then the gravitational force will
be proportional to
Hence, if the distance is reduced to half, then the gravitational force becomes four
times larger than the previous value.
Similar questions
Computer Science,
7 months ago
English,
7 months ago
Hindi,
7 months ago
Math,
1 year ago
Math,
1 year ago