how does the force of gravition between two object change when the distance between then is reeduced to half .
Answers
Answered by
4
F=Gm1m2/r^2
if r is reduced to half then r=1/2r
F=Gm1.m2/(1/2r)^2
F= Gm1.m2/(1/4r^2)
F= 1/4.Gm1m2/r^2
F= 1/4.F
if r is reduced to half then r=1/2r
F=Gm1.m2/(1/2r)^2
F= Gm1.m2/(1/4r^2)
F= 1/4.Gm1m2/r^2
F= 1/4.F
Answered by
1
☺ Hello mate__ ❤
◾◾here is your answer...
According to the universal law of gravitation, gravitational force (F),
F∝ 1/r^2
If distance r becomes r/2, then the gravitational force will be proportional to
F ∝ 1/ (r/2)^2 ∝ 4/r^2
Hence, if the distance is reduced to half, then the gravitational force becomes four times larger than the previous value.
I hope, this will help you.
Thank you______❤
✿┅═══❁✿ Be Brainly✿❁═══┅✿
Similar questions