Question

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Answer 1

Answer:

When a particle is protected up from an inclined plane of angle of inclination β.

acceleration of the object parallel to the surface is ..

(a) gcosβ (b) -gcosβ (c) gtanβ (d) gsinβ

solution : as angle of inclination is β, component of weight along plane is mgsinβ [ as shown in figure ]

so acceleration of the object along plane or parallel to the surface is mgsinβ/m = gsinβ

Therefore acceleration of the object parallel to the surface is gsinβ

Answer 2

Explanation:

Mark as brainlist answer