how does the kinetic energy change if its momentum is halved
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ke=p^2/2m is the answer
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Given: Initial momentum = p₁
Initial Kinetic Energy= E₁
Final momentum p₂ = p₁/2
Mass of an object = m
To Find: Final Kinetic Energy, E₂
Solution:
Formula used-
- Kinetic Energy, E = (momentum)²/ 2 x mass
- E = p²/ 2m
- E ∝ p²
Therefore,
E₁ = (p₁)²/ 2m
E₂ = (p₂)²/ 2m
As, p₂ = p₁/2
So, E₂ = (p₁/2)² / 2m
On dividing E₁ and E₂
E₁/ E₂ = [(p₁)²/ 2m] / [(p₁/2)² / 2m]
E₁/ E₂ = 4/ 1
E₂ = E₁ / 4
This means, if momentum is halved, kinetic energy is reduced by 4 times its original value.
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