how does the number of particles scattered, in a alpha ray scttaering experiment, vary with a variation in angle of scattering?
Answers
Answer:
Rutherford and Royds showed that an alpha particle was a helium-4 nucleus in 1909. Rutherford knew that alpha radiation had a range of about 5 cm in air, and its range in denser materials had been measured. Experiment: Alpha, beta and gamma radiations can be distinguished by their penetrating powers.
Explanation:
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Answer:
We notice that the differential cross-section diverges as the scattering angle goes to zero.
However we note from that small angle scattering implies a large impact parameter.
The distance of the incident particle from any nucleus can only grow to about half of the
distance between the nuclei in the gold foil. In fact, the total number of particles scattered
into a given solid angle is the differential cross-section multiplied by the flux, multiplied by
the number of nuclei in the foil - or more precisely in the part of the foil that is ‘illuminated’
by the incident α-particles. We assume that the foil is sufficiently thin so that multiple
scatterings are very unlikely and we can make the approximation that all the nuclei lie in
a single plane.
Explanation: