How does the procedure of drawing a histogram differ when class intervals are unequal in comparison to equal class intervals in a frequency table?
Answers
Answered by
0
Answer:
Procedure Of Drawing A Histogram Differ When Class-Intervals Are Unequal In Comparison To Equal Class-Intervals In A Frequency Table. In The Case Of Equal Class-Intervals, No Adjustment Is Made. ... In Case Of Unequal Class-Intervals, Frequencies Of Unequal Class-Intervals Are Adjusted.
Step-by-step explanation:
Answered by
15
Answer:
Therefore, the principal value of tan−1(−3 ) is −3π
Similar questions