How does the resistance of a wire change when the diameter is tripled ?
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we know that resistance is inversly proportional to area of cross section so if diameter is thribled,
let diameter at first be d radius be r length be l and resistivity which is a constant be p.after thribled, everythings same exept radius which becomes 3/2r when d2 is 3d
d=2r thats why
now, R1=Pl/pie(r^2)
R2=Pl/(pie)(r^2)(9/4)=Pl/pie(r^2) x4/9
=>R2=R1(4/9)
so resistance changes by 4/9 times. CHEERS
if yr satisfied let me know
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