How does the resistance of a wire vary with its diameter?
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How does resistance vary with diameter?
Simply Stated:
As electrons move across a wire, they constantly collide with atoms making up a wire. These collisions impede the flow of electrons and are what cause the wire to have resistance.Thus, if the diameter of the wire were larger, it would only make sense that the electrons don't collide as much, therefore creating less resistance due to a larger wire. This is all in accordance to Ohm's law. The resistance is the ratio of the voltage difference across an object to the current that passes through the object due to the existence of the voltage difference. If the object is made of a material that obeys Ohm's Law, then this ratio is constant no matter what the voltage difference is. Consider a copper wire that passes some amount of current, say 1 A,when a voltage difference of 1 V is applied between the ends of the wire. Now consider an identical but separate wire connected across that same 1V potential difference. You would expect that it would also conduct 1 A. Now think of joining those two wires together side by side into one, thicker wire. It is reasonable to expect that this wire should carry 2 A of current if the potential difference across the wires is still 1 V. Thus, the new, thicker wire will have a reduced resistance of 1/2 Ohm compared to the original wire with its resistance of 1 Ohm. Basically, a thicker wire creates additional paths for current to flow through the wire
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