Question

how does the resistence R changes if the thickness of a wire isdoubled?

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Answer 1

ᕼᗝᒪᗩ ᗰᗩ丅ᗴ.. ᕼᗴᖇᗴ Ꭵᔕ ᑌᖇ ᗩᑎᔕ;

As a աɨʀɛ ɢɛts ʟօռɢɛʀ ɨts ʀɛsɨstaռċɛ ɨռċʀɛasɛs, aռɖ as ɨt ɢɛts tɦɨռռɛʀ ɨts ʀɛsɨstaռċɛ aʟsօ ɨռċʀɛasɛs ɮɛċaʊsɛ ɨts ċʀօss sɛċtɨօռaʟ aʀɛa ɖɛċʀɛasɛs. ɖօʊɮʟɨռɢ tɦɛ ʟɛռɢtɦ աɨʟʟ ɖօʊɮʟɛ tɦɛ ʀɛsɨstaռċɛ, ɮʊt tɦɛ աɨʀɛ aʟsօ ʍʊst ɢɛt tɦɨռռɛʀ as ɨt ɨs stʀɛtċɦɛɖ, ɮɛċaʊsɛ ɨt աɨʟʟ ċօռtaɨռ tɦɛ saʍɛ aʍօʊռt օʄ ʍɛtaʟ ɨռ tաɨċɛ tɦɛ ʟɛռɢtɦ..

ᴴᵒᵖᵉ ᶤᵗ ʰᵉˡᵖˢ ᵘ!! ᴾˡᶻᶻ ᵐᵃʳᵏ ᵐᵉ ᵃˢ ᴮᴿᴬᴵᴺᴸᴵᴱˢᵀ.. ~$€❤♡♡♡♡

Answer 2

$\huge\mathbb{\orange{QUESTION-}}$

How does the resistence R changes if the thickness of a wire is doubled?

$\huge\mathbb{\orange{ANSWER-}}$

As we know that ⎯

Resistance is directly proportional to lenght of the wire ,

$\large{\boxed{\sf R=\rho \dfrac{l}{A}}}$

$\implies{\sf \red{R\:\:\:\alpha\:\:\: l}}$

$\implies{\sf \red{R\:\:\:\alpha\:\:\:\dfrac{1}{A}} }$

Here , we can see that Resistance is directly proportional to length , and inversely proportional to area.

⛬ According to Question ,

If the lenght of wire is doubled , therefore resistance will also be doubled.