How does the total surface area of a box change if 1)each dimension is doubled?
2)each dimension is tripled?
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Solution -
Let the side of original cube be x
Total Surface Area of original cube
= 6 × x² [ ∵ TSA of cube = 6 × Side² ]
1. So, the side of new cube[I] be 2x
Total Surface Area of new cube1
= 6 × (2x)²
2. So, the side of new cube[II] be 3x
Total Surface Area of new cube2
= 6 × (3x)²
According to Question,
1... TSA of new cube[I] / TSA of ori. cube
= 6 × (2x)² / 6 × x²
= 4x² / x²
= 4
∴ Total Surface Area of new cube[I] = 4 times Total Surface Area of original cube
2... TSA of new cube[II] /TSA of ori. cube
= 6 × (3x)² / 6 × x²
= 9x² / x²
= 9
∴ Total Surface Area of new cube[II] = 9 times Total Surface Area of original cube
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