How doy ou solve 2v−4+2(4v+6)=−2(v+5)?
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Solution:
2v−4+2(4v+6)=−2(v+5)
=>2v-4+2(4v+6)+2(v+5)=0
=> 2v-4+8v+12+2v+10=0
=> 2v+8v+2v-4+12+10=0
=>(2+8+2)v+18=0
=> 12v=-18
=> v = (-18)/12
=> v = (-6×3)/(6×2)
After cancellation,we get
=> v = -3/2
Therefore,
v = -3/2
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