How far apart the electrons be if the force each exerts on the other is equal to the weight of the electron
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Answered by
207
let r distance between two electrons .
F = Force exerted by one electrons to other
F = Ke²/r²
weight of electron = mg
a/c to question ,
F = mg
Ke2/r² = mg
9×10^9 × {1.6 × 10^-19 }²/r² = 9.1 × 10^-31 × 10
r² ={ 9 ×2.56/9.1 } × 10^-38+30+9
= 25.31
r = 5.03 m
F = Force exerted by one electrons to other
F = Ke²/r²
weight of electron = mg
a/c to question ,
F = mg
Ke2/r² = mg
9×10^9 × {1.6 × 10^-19 }²/r² = 9.1 × 10^-31 × 10
r² ={ 9 ×2.56/9.1 } × 10^-38+30+9
= 25.31
r = 5.03 m
Nivea11:
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Answered by
3
Explanation:
mass of electron ,m =9.1 ×10-³¹
weight of electron ,W =MG
= 9.1×10-³¹ × 10
= 9.1 × 10‐³⁰ N
GIVEN,
MG = 1/4 pie E0 q²/r²
9.1×10‐³⁰ = 9×20⁹×(1.6×10‐19)²/r²
= r² = 9×19⁹×2.50×10‐³⁸/9.1×10‐³⁰
= 2.53×10
r² = 25.3
r = 25.3
r = 5m
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