how far apart the two electrons be if the force between them equals the weight of electron ?what in case of protons
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★ Here is your Answer ★
ke^2 / r^2 = m g
r = e [k / (m g)]^1/2
then
1) r = 1.6x10^-19 [9x10^9 / (9.1x10^-31 ×9.8)]^1/2 = 5.08 m [electrons]
2) r = 1.6x10^-19 [9x10^9 / (1.67x10^-27×9.8)]^1/2 = 0.12 m [protons]
HOPE HELPED♥♥♥
★ Here is your Answer ★
ke^2 / r^2 = m g
r = e [k / (m g)]^1/2
then
1) r = 1.6x10^-19 [9x10^9 / (9.1x10^-31 ×9.8)]^1/2 = 5.08 m [electrons]
2) r = 1.6x10^-19 [9x10^9 / (1.67x10^-27×9.8)]^1/2 = 0.12 m [protons]
HOPE HELPED♥♥♥
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